Ameteoroid, heading straight for earth, has a speed of 14.8 km/s relative to the center of earth as it crosses our moon's orbit, a distance of 3.84 × 108 m from the earth's center. what is the meteroid’s speed as it hits the earth? you can neglect the effects of the moon, earth’s atmosphere, and any motion of the earth. (g = 6.67 × 10 -11 n ∙ m2/kg2, mearth = 5.97 × 1024 kg)

v = 112.424 km / s

Explanation:

Given:

d = 3.84 x 10 ⁸ m  , R = 63 x 10³ m  , m earth = 5.97 x 10²⁴ kg  ,  G = 6.67 x 10⁻¹¹ N * m² / kg² , v₁ = 14.8 x 10 ³ m / s

Using the equation

KE + PE = initial KE + PE

¹/₂ * m * v₂² - G * m/ R = ¹/₂ * m * v₁² - G * m/(R+d)

v₂² = v₁² + 2*G * m [ 1/R - 1/(R+d) ]

v₂² = 14.8 x 10 ³ m /s + 2 * 6.67 x 10⁻¹¹ N * m² / kg² * 5.97 x 10²⁴ kg  [ 1 / 63 x 10³m - 1 / ( 63 x  10³ + 3.84 x 10⁸ m ) ]

v = √ 1.26 x 10¹⁰ m² / s²

v =  112.424 x 10³ m/s  

v = 112.424 km / s

c because the news are a source of information of things that happen on the daily and shows evidence about that particular topic

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.