In an rl series circuit, an inductor of 3.54 h and a resistor of 7.76 ω are connected to a 26.6 v battery. the switch of the circuit is initially open. next close the switch and wait for a long time. eventually the current reaches its equilibrium value. at this time, what is the corresponding energy stored in the inductor?

Energy stored in inductor will be 20.797 J

Explanation:

We have given inductance L = 3.54 H

And resistance R = 7.76 ohm

Battery voltage V = 26.6 VOLT

After very long time means at steady state inductor behaves as short circuit

So  current

Now energy stored in inductor

So energy stored in inductor will be 20.797 J

the answer would be 32*f

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