Acircular coil of radius r = 5 cm and resistance r = 0.2 is placed in a uniform magnetic field perpendicular to the plane of the coil. the magnitude of the field changes with time according to b = 0.5 e-0.2t t. what is the magnitude of the current induced in the coil at the time t = 2 s? a circular coil of radius r = 5 cm and resistance r = 0.2 is placed in a uniform magnetic field perpendicular to the plane of the coil. the magnitude of the field changes with time according to b = 0.5 e-0.2t t. what is the magnitude of the current induced in the coil at the time t = 2 s? 1.3 ma 7.5 ma 2.6 ma 4.2 ma 9.2 ma

the question is incomplete, the complete question is

"A circular coil of radius r = 5 cm and resistance R = 0.2 ? is placed in a uniform magnetic field perpendicular to the plane of the coil. The magnitude of the field changes with time according to B = 0.5 e^-t T. What is the magnitude of the current induced in the coil at the time t = 2 s?"

2.6mA

Explanation:

we need to determine the emf induced in the coil and y applying ohm's law we determine the current induced.

using the formula be low,

where B is the magnitude of the field and A is the area of the circular coil.

First, let determine the area using where r is the radius of 5cm or 0.05m

since we no that the angle is at

we determine the magnitude of the magnetic filed

the Magnitude of the voltage is 0.000532V

Next we determine the current using ohm's law

weight of the box is given as

here this is placed on the inclined of angle 42 degree

now this weight will have two components one is along the incline other is perpendicular to it

so here we need to apply a force parallel to incline opposite to its component of weight

so here the component of weight is given as

here we have

so it requires 75 n force to move it upwards