Wo parallel-plate capacitors have the same dimensions, but the space between the plates is filled with air in capacitor 1 and with plastic in capacitor 2. each capacitor is connected to an identical battery, such that the potential difference between the plates is the same in both capacitors. compare the magnitudes of the electric fields between the plates, and , and the magnitudes of the free charges on the plates, and .

Explanation:

Let the dielectric constant of plastic be K . Then , if the capacity of air capacitor is C , the capacity of plastic capacitor will be KC.

If the emf of battery be V then V will be the potential difference between plates of both of them

electric field E = V/d for air capacitor

For plastic capacitor electric field = E / k

Their ratio

=  E /E / k

Magnitude of free charge in air capacitor

Q₁= V x C= CV

Magnitude of free charge in plastic capacitor

Q₂  = V x KC= KCV

Q₂ / Q₁ = K

luster is not a good characteristic to use by itself because luster is the property of minerals that indicates how much the surface of a mineral reflects light. the luster of a mineral is affected by the brilliance of the light used to observe the mineral surface.

get the total number of pieces of fruit and divide it by 4 to get the average. the result is the answer to the problem. 14 total number of fruits and there are 4 members. 14 divided by 4 is equals to 3.5.