Arocket is fired vertically upward. at the instant it reaches an altitude of 2700 m and a speed of 274 m/s, it explodes into three equal fragments. one fragment continues to move upward with a speed of 235 m/s following the explosion. the second fragment has a speed of 484 m/s and is moving east right after the explosion. what is the magnitude of the velocity of the third fragment? answer in units of m/s.

Explanation:

Given

initial velocity of particle u=274 m/s

one Particle moves up with velocity of v=235 m/s

and other moves u=484 m/s towards east

let and be the velocity of third Particle is Y and x direction

conserving momentum in y direction  

Now conserving momentum in  x direction

Net Velocity of third Particle

answer: 802.3 kilo joules of energy represents 191.75 kilo calorie of energy.

explanation:

energy released during combustion of one mole methane = 802.3 kilo joules

if 1 kilo joule = 0.239006   kilo calorie

then ,802.3 kilo joule will be = 802.30.239006 kilo calorie

802.3 kilo joule = 191.75 kilo calorie

hence, the energy in kilo calorie is 191.75 kilo calorie.

iron would move it is magnetic there is a mag field around the current in the wire