Adriver slammed on her brakes and came to a stop with constant acceleration. measurements on her tires and skid marks on the pavement indicate that she locked her car's wheels, the car traveled 58.52 meters before stopping, and the coefficient of kinetic friction between the road and her tires was 0.750. how fast was she driving

u = 29.22 m/s

Explanation:

distance (s) = 58.52 m

coefficient of kinetic friction (k) = 0.75

final velocity (v) = 0 m/s

acceleration due to gravity (g) = 9.8 m/s^{2}

How fast was she driving (u)

we can get how fast she was driving by using the formula below

s = ut -  ...equation 1

where

        from v = u - at  (recall that v = 0)

        0 = u - at, therefore t = u/a = u/kg

now substituting the required values above into equation 1 we have

s =

s =

u =

u =

u = 29.22 m/s

multiple

we have been given a quadratic function and we need to restrict the domain such that it becomes a one to one function.

we know that vertex of this quadratic function occurs at (5,2).

further, we know that range of this function is .

if we restrict the domain of this function to either or , it will become one to one function.

let us know find its inverse.

upon interchanging x and y, we get:

let us now solve this function for y.

hence, the inverse function would be if we restrict the domain of original function to and the inverse function would be if we restrict the domain to .