Starting from rest, christina experiences 24.5 m/s2 of acceleration to take off from an aircraft carrier for 5 seconds. how long does the runway need to be? round to the nearest meter.

The length of the runway to the nearest meter is 306 m.

Explanation:

Given:

Initial velocity of Christina is,

Time taken is,

Acceleration experienced by Christina is,

The length of the runway is,

Now, we use Newton's equation of motion that relates the distance, initial velocity, time and acceleration.

So, we have the following equation of motion:

Plug in all the given values and solve for 'd'. This gives,

Therefore, the length of the runway to the nearest meter is 306 m.

the minimum constant speed at which she can catch the train is 2.7 m/s

given:

acceleration = 0.6

time = 4.5 s

to find:

velocity = ?

formula used:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

solution:

from 1st kinematic equation we get,

v = u + at

u = initial speed of train = 0 m/s

v = final speed of the train

a = acceleration of the train

t = time

v = 0 + (0.6 × 4.5)

v = 2.7 m/s

the minimum constant speed at which she can catch the train is 2.7 m/s

the inner core.

good luck: )

klicker