Acircular conducting loop of radius 23.0 cm is located in a region of homogeneous magnetic field of magnitude 0.500 t pointing perpendicular to the plane of the loop. the loop is connected in series with a resistor of 265 ω. the magnetic field is now increased at a constant rate by a factor of 2.50 in 23.0s. calculate the magnitude of the induced emf in the loop while the magnetic field is increasing.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.