Apressure transducer that behaves as a second order system is supposed to have a damping ratio of 0.7, but some of the damping fluid has leaked out leaving us with an unknown damping ratio. when the transducer is subjected to a harmonic input of 1850 hz the phase angle between the input and the output is 45°. the manufacturer states that the natural frequency of the transducer is 18,500 rad/s. (a) what is the dynamic error in the transducer output for a harmonic pressure signal of 1200 hz? (b) if the transducer indicates a pressure amplitude of 50 psi, what is the true (input) pressure amplitude?

    m₁v₁ + m₂v₂ = (m₁ + m₂)vmomentum is conserved.the left-hand side of the equation represents the momentum in the system before the collision.the right-hand side represents the momentum in the system after the collisionm₁ and v₁ represents the mass and the velocity of the physics blockm₂ and v₂ represents the mass and velocity of the ball of puttyv represents the final velocity of the combined mass.the question states the two masses stick together. they combined mass has its own velocity with the body mass the sum of the two objects' massestheir combined momentum is (m₁ + m₂)vto find the magitude of (m₁ + m₂)v, we need to add the vectors on the left-hand side of the equation: m₁v₁ + m₂v₂.note the diagram. i have positioned the vectors in accordance with their directions.the magnitude of the resultant can be calculated using the pythagorean theorem since this is a right triangle situation (north and west are perpendicular)|(m₁ + m₂)v| =  √[ (m₁v₁)² + (m₂v₂)² ]|(m₁ + m₂)v| =  √[ (1.5kg·8.0m/s)² + (0.40kg·20m/s)² ]|(m₁ + m₂)v| =  14.4 kg m/sfor two significant figures (assuming that 20m/s is two), this rounds to 14 kg m/s

C. it comes from the core of the earth.