An all female guitar septet is getting ready to go on stage. the lead guitarist, kira, who is always in tune, plucks her low e string and the other six members, sequentially, do the same. each member records the initial beat frequency fbeat, i between her low e string and kira's low e string. rank each member on the basis of the initial frequency of their low e string. rank from largest to smallest : diane : fbeat, i = 0 hzfreja : fbeat, i = 3 hzaiko: fbeat, i = 3 hzchandra: fbeat, i = 1 hzevita: fbeat, i = 5 hzbuffy : fbeat, i = 4 hz

No because scientist are still changing there mines today so they are not correct to this day

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j