With what minimum speed must athlete leave the ground in order to lift his center of mass 1.80 m and cross the bar with a speed of 0.65 m/s ?

answer:

fran must leave the ground at at least 6.3 ms^-1 in order to barely make it over the jump.

explanation:

well gravity is -9.8 ms^-1, the height is 2 metres and the final velocity is 0.7 ms^-1. we can use:

v^2 = u^2 + 2as, and solve for u.

v^2 - 2as = u^2

u = sqrt(v^2 - 2as)

= sqrt(0.7^2 - 2 * -9.8 * 2)

= sqrt(0.49 + 39.2)

= sqrt(39.69)

= 6.3 ms^-1

are there options? cause you ain’t. real specific

momentum of soft ball three times less than baskey ball