![Ek=\frac{1}{2} *m*v^{2} \\where:Ek= kinetic energy [J]\\m = mass of the ball [kg]\\v = velocity of the ball [m/s]](/tpl/images/0416/5621/7095e.png)
![Ek=\frac{1}{2}*(2)*(3^{2} )\\ Ek=9[J]\\](/tpl/images/0416/5621/a6a7f.png)
![Ek=Ep\\where\\Ep=potential energy [J]\\Ep=m*g*h\\where\\g=gravity = 9.81[m/s^2]\\h=height reached [m]\\](/tpl/images/0416/5621/51106.png)
![h=\frac{Ep}{m*g} \\h=\frac{9}{2*9.81} \\\\h=0.45 [m]](/tpl/images/0416/5621/d4126.png)
A2 kg ball is moving 3 m/s when it starts rolling up a hill.
what is the maximum height...
Physics, 13.12.2019 05:31, bobthebattlebot
A2 kg ball is moving 3 m/s when it starts rolling up a hill.
what is the maximum height that the ball will reach?
(ignore friction and do not include units)
Answers: 3
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