Agrinding wheel is spinning with an initial angular velocity +ω0. when its motor is turned off at t=0, it begins to slow down with an angular acceleration −α. derive an expression for the number of revolutions that the wheel will rotate through before coming to rest. express your answer in terms of the variables ω0 and α, and the constant π.

Explanation:

Given

initial angular velocity is

when motor is turned of it started decelerating with  angular acceleration

angle turned before coming to halt

here final angular velocity is zero

No of revolutions will be

d

explanation:

v=uf/(u-f)

= 5.10/(5-10) convex lens has positive focal length

=50/-5

=-10 cm (formed at other side)

the simple machine has three main features. they are:

fulcrum is the center point or pivot point of the machine. effort is input force/ applied force. load is external force/ output.

the keisha 's machine labels are

x : load

y: fulcrum

z: lever