Apail of water is rotated in a vertical circle of radius r = 1.6 m . the acceleration of gravity is 9.8 m/s 2 . r v what is the minimum speed of the pail at the top of the circle if no water is to spill out? answer in units of m/s.

3.95 m/s

Explanation:

Given

radius of circle

Water will not spill if the centripetal acceleration is greater than acceleration due to gravity

i.e.

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

we're given that v₀ = 0 and a = 5.4 m/s². therefore, since v = at + v₀ for constant acceleration the equation for velocity is

after 28s,

m/s

which i would round to 150 m/s as my final answer