Compare the magnitude of the magnetic field at the center of a circular current loop of radius 50 mm with the magnitude of the magnetic field at the center of a solenoid of the same radius and with 2.0 turn per millimeter. assume the current is the same through the current loop and the solenoid.

Answer

given,

Radius of the circular current = 50 mm

Number of turn = M = 2 turn/mm

magnetic field at the center of the loop

magnetic field at the center of  solenoid

now, ratio

=

=

=

                            B' = 200 B

magnetic field inside the solenoid is 200 times the magnetic field of loop.

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j