Find a numerical value for rhoearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of the earth, g=6.67×10−11m3/(kg⋅s2), and a value of g at the surface of 9.80m/s2.express your answer to three significant figures.

density = 5520 kg/m^3

Explanation:

given that

radius of earth = 6378 km

G = 6.67 x 10⁻¹¹ m³/kg.s²

g = 9.80 m/s²

we know,

mass of earth

M = 5.972 x 10²⁴ kg

density =

V = volume of the earth = 4/3πr³

V = 4/3 x 3.14 x (6378  x 10³)³

V = 1.08 x 10²¹ m³

density =

density = 5.52 x 10³  kg/m^3

density = 5520 kg/m^3

object 2 because all the other ones are wrong

double the distance = divide strength by 4