Acareful photographic survey of jupiter's moon io by the spacecraft voyager 1 showed active volcanoes spewing liquid sulfur to heights of 70 km above the surface of this moon. if the value of g on io is 2.0 m/s2 , estimate the speed with which the liquid sulfur left the volcano.

The concept used to solve this problem is that given in the kinematic equations of motion. From theory we know that the change in velocities of a body is equivalent to twice the distance traveled by acceleration, in other words:

Where,

Final and initial velocity

a = Acceleration

x = Displacement

For the given case, the displacement is equivalent to the height (x = h) and the acceleration is the same gravitational acceleration (a = g). In turn we do not have initial speed therefore

Our values are given as

Replacing we have that,

Therefore the speed with which the liquid sulfur left the volcano is 529.15m/s

does anyone know or what?

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.