Aspring (k = 790 n/m) has a length of 48 cm when zero net force is applied to it. what will its length be when 230 n of force is applied to stretch it?
question 3 options:

3.4 m

0.77 m

3.9 m

0.29 m

0·77 m

Explanation:

Given

Spring constant = k = 790 N/m

Equilibrium length of the spring = 48 cm = 0·48 m

Force applied = 230 N

Let the x m be the length of the spring when 230 N of force is applied on it

Spring force that is acting will be k × (x - 0·48)

When applied force is 230 N, the spring force will also be equal to 230 N as there will be equilibrium

∴ k × (x - 0·48) = 230

790 × (x - 0·48) = 230

x = (230 ÷ 790) + 0·48

x = 0·29 + 0·48

∴ x = 0·77 m

∴ Length of the spring when 230 N of force is applied to stretch it = 0·77 m

answer: he got 23

explanation:

i think the answer is tomato juice? not entirely sure though