An train car of total mass of 13000 kg is pulling into a station and slowing down with an acceleration of -4.56 m/s^2. before the train pulls into the station, a group of 7 stowaway jump off the train. each stowaway has a mass of 66 kg. if the braking force on the train remains the same, what will be the acceleration of the train once the stowaways jump out of the train?

Explanation:

F=ma where F is the force, m is the mass of object and a is acceleration

Initial mass is 13000 Kg

Final mass=1300-(66*7)=12538 Kg

where and are initial and final mass respectively, and are initial and final acceleration respectively

By substitution

1/0.14nm = 10^10/1.4 a lot

russian is not my first language, so i'm afraid i can't write out an answer in russian, but hopefully you can find a way to do so. here's my best translation of the problem: you're given a plot of a particle's position in one-dimensional space over time, and you're asked to find either the total distance traveled by the particle after 6 seconds had elapsed, or the total displacement of the particle after 6 seconds.

if you want the total distance traveled, you would first need to determine the particle's velocity as a function of time, then integrate that over the 6-second interval. we know the position function is quadratic with roots at 0 and 6, so we have

where is unknown. because the position is parabolic, there is symmetry about the midpoint at , and we know that

so that the position function is

which means the velocity is

then the total distance traveled is

so the total distance traveled is 20 m.

on the other hand, if you want to find displacement: the particle starts at and ends at , so its displacement is 0.