Aperson pulls on a 7.4 kg crate against a 22 newton frictional force, using a rope attached to the center of the crate. if the the crate began with a speed of 1.6 m/s and speeded up to 2.6 m/s while being pulled a horizontal distance of 2.0 meters. what is the work in j done by the force applied by the rope on the crate?

Work done will be 59.54 J

Explanation:

We have given that person pulls a 7.4 kg crate against 22 Newton frictional force

So frictional force

Balance force is given by

We have given initial speed u = 1.6 m /sec

And final speed v = 2.6 m/sec

Distance s = 2 m

From third equation of motion we know that

So

We know that work done is given by

i just did an experiment like this in my science class. also the answer is yes, it will get separated because they are two opposites meaning if they are opposite they can not attract.

hope this .!