A2.00 m-long 6.00 kg ladder pivoted at the top hangs down from a platform at the circus. a 42.0 kg trapeze artist climbs to a point where her center of mass is at the center of the ladder and swings at the system's natural frequency. the angular frequency (in s −1) of the system of ladder and woman is

f= 0.48 s⁻¹

Explanation:

Given that

Mass of the ladder ,m= 6 kg

L= 2 m

Mass of artist ,M= 42 kg

The total moment of inertia of the both ladder and artist ,I

Here

I=50 kg.m²

The angular frequency f given as

Here

D=1 m

f= 0.48 s⁻¹

the working equation for the angular size is the product of the physical size and 360 degrees divided by the product of two pi and distance from earth. the minimum size would be 0.559 degrees while the maximum size would be 0.49 degrees. 

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