You want the current amplitude through a 0.450-mh inductor (part of the circuitry for a radio receiver) to be 1.80 ma when a sinusoidal voltage with amplitude 12.0 v is applied across the inductor. what frequency is required?

2.36 x 10^6 Hz

Explanation:

We know ;,

Iamp = 1.8mA

L = 0.45mH

VL = 12V

VL = IwL

VL = I x 2π x f x L

f = VL / (I x 2π x L)

f = 12 V/ (1.8mA x 2π x 0.45mH)

f = 12/(1.8x10^-3 x 2π x 0.45 x 10^-3)

f = 2.36 x 10^6 Hz

answer: option c.

explanation:

dec 23, 2016 - a load of bricks weighing 680 n a distance of 10 m across a parking lot. if if the worker pushes the cart with a constant force of 209 n, what work= force x distance = 220 n x 10 m = 2200 n.m = 2200 j i don't know where the person got it from, but the initial part, work= force x distance me.