Acar traveling 23 m/s begins to decelerate at a constant rate of 5 m/s^2 . after how many seconds does the car come to a stop? (use symbolic notation and fractions where needed.)

t = 4.6 s

Explanation:

given,

initial velocity of the car = 23 m/s

declaration rate of car = 5 m/s²

final velocity of the car = ?

time taken to stop the car = ?

using equation of motion to solve the question

v = u + a t

v is final velocity

u is the initial velocity

0 = 23 - 5 t

we have used negative sign because there is deceleration

5 t = 23

t = 4.6 s

time taken to stop the car is equal to t = 4.6 s

r=rho l/a where a is the area, l is the length and rho is resistivity so the greater the area the lesser the resistance thats why the earth pin is thicker bcos current follow the shortest path, so less resistive .