Athin, light wire 75.2 cm long having a circular cross section 0.560 mm in diameter has a 25.2 kg weight attached to it, causing it to stretch by 1.10 mm . you may want to review (page) . for related problem-solving tips and strategies, you may want to view a video tutor solution of a stretching elevator cable. part a what is the stress in this wire? express your answer in pascals.

The stress is calculated as

Solution:

As per the question:

Length of the wire, l = 75.2 cm = 0.752 m

Diameter of the circular cross-section, d = 0.560 mm =

Mass of the weight attached, m = 25.2 kg

Elongation in the wire,

Now,

The stress in the wire is given by:

         (1)

Now,

Force is due to the weight of the attached weight:

F = mg =

Cross  sectional Area, A =

Using these values in eqn (1):

answer: the correct answer is 1.

explanation: there are various process in which a radioactive nuclei decays:

1) alpha decay: in this process, a heavier nuclei decays into lighter nuclei by releasing alpha particle. the mass number is reduced by 4 units.

2) electron capture: in this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. simply, a proton and an electron combines together to form a neutron. mass number does not change in this process.

3) gamma ray emission: it is a decay process in which an unstable nuclei gives excess energy by a spontaneous electromagnetic process. this decay releases . this process does not change the mass number.

4) positron emission: it is a type of decay process, in which a proton gets converted to neutron and an electron neutrino. this is also known as -decay. in this the mass number remains same.

from the above information, we see that only alpha-decay is producing a change in the mass number of the nucleus.