2. how does kinetic energy affect the stopping distance of a vehicle traveling at 30 mph compared to the same vehicle traveling at 60 mph? 3. how does kinetic energy affect the stopping distance of a small vehicle compared to a large vehicle? 4. keeping in mind the kinetic energy of a moving vehicle, how can a driver best prepare to enter sharp curves in the roadway? 5. using information about natural laws, explain why some car crashes produce minor injuries and others produce catastrophic injuries.

1)It will take less energy to stop a car moving 30 kmh than 60 kmh. the momentum of the car moving with greater velocity will require greater force to stop it. And more forces of inertia will also be acting on it.

2)same principle apply here as well. A car with more mass is moving with greater momentum even though the velocity may be same.

3)it is advised to enter a curve at its edges. As the centrifugal force required to keep the car in the arc and from flipping over will be least.

4) it depends on the nature of crash. And the angle at which the force acted on the car and subsequently on the passenger. A side on collsion means there is less distance between the object hitting the car and the passenger. That means the car has a less chance of absorbing the force and the passenger is subject to a greater force.

you'd use the equation that establishes a relationship between  energy  and  wavelength, which looks like this

e=h⋅cλ, where

λ  - the wavelength of the photon; c  - the speed of light, usually given as  3⋅108m/s; h  -  planck's constant, equal to  6.626⋅10−34j s

plug the value you were given for the energy of the photon in the above equation to get the wavelength

e=h⋅cλ⇒λ=h⋅ce

λ=6.626⋅10−34js⋅3⋅108ms−1.257⋅10−24j=1.581⋅10−1m