One end of a metal rod is in contact with a thermal reservoir at 699. k, and the other end is in contact with a thermal reservoir at 101. k. the rod and reservoirs make up a closed system. if 6970. j are conducted from one end of the rod to the other uniformly (no change in temperature along the rod) what is the change in entropy of a) each reservoir, b) the rod and c) the system?

a)ΔS₁ = - 9.9 J/K

ΔS₂ = 69 J/K

b)The entropy change for the rod = 0 J/K

c)ΔS = 59.1 J/K

Explanation:

Given that

T₁ = 699 K

T₂= 101 K

Q= 6970 J

Change in entropy given as

For 699 K:

ΔS₁ = - 9.9 J/K  ( Negative because heat is leaving from the system)

For 101 K;

ΔS₂ = 69 J/K

The entropy change for the rod = 0 J/K

Entropy  change for the system

ΔS = ΔS₂  + ΔS₁

ΔS = 69 -9.9 J/K

ΔS = 59.1 J/K

a coal burning power plant

when two balls of the different masses are dropped from equal height, they reach the ground at the same time .this is because they experience the same acceleration.

the acceleration is independent of mass.

thus when they are dropped they will always maintain the same velocity and travel the same distance (neglect air resistance of course) at the same time.