What is the average power output of an athlete who can life 9.0 * 10^2 kg 2.5 m in 2.0 s?

11025 W

Explanation:

Given that athlete can lift a mass of 900 kg by 2·5 m in 2 s

Average power output is defined as the work done per unit time∴ Average power output = (work done) ÷ (time taken)

Here on the object the force that acts is the weight of that object

∴ Force on that object = (mass of the object) × (acceleration due to gravity) = 900 × 9·8 = 8820 N

∴ Person requires this much force to lift that object

Work done on the object is defined as the dot product of force and displacement

∴ Work done = 8820 × 2·5 =22050 J

Power = 22050 ÷ 2 = 11025 W

∴ Average power output of the athlete = 11025 W

Answer: buoyancy forceexplanation: in simple terms, the principle states that the buoyancy force on an object is equal to the weight of the fluid displaced by the object, or the density of the fluid multiplied by the submerged volume times the gravitational acceleration, g. this is also known as upthrust.

Answer: it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.explanation:   we have equation of motion ,where s is the displacement, a is the acceleration, u is the initial velocity and t is the time taken.average velocity = displacement/ time taken.average velocity = 10.69 miles/hr = 10.69*1.6*1000/(60*60) = 4.75 m/s4.75 = s/ts = 4. 1we also have acceleration = 2.18 m/s², initial velocity = 0 m/sso it will take   4.36 seconds to reach her average velocity 10.69 miles/hour.