Suppose a clay model of a koala bear has a mass of 0.205 kg and slides on ice at a speed of 0.720 m/s. it runs into another clay model, which is initially motionless and has a mass of 0.320 kg. both being soft clay, they naturally stick together. what is their final velocity (in m/s)? (enter the magnitude.)

Final velocity, v = 0.28 m/s

Explanation:

Given that,

Mass of the model,

Speed of the model,

Mass of another model,

Initial speed of another model,

To find,

Final velocity

Solution,

Let V is the final velocity. As both being soft clay, they naturally stick together. It is a case of inelastic collision. Using the conservation of linear momentum to find it as :

V = 0.28 m/s

So, their final velocity is 0.28 m/s. Hence, this is the required solution.

  the grams     of oxygen gas   that can be produced     is 20.6   grams of o₂

calculation

2liclo₃ →   2 licl + 3 o₂

step 1:   find the moles of liclo₃

moles = mass÷ molar mass

from periodic table the molar mass of liclo₃ =6.9 +35.5   +(16 x3) =90.4 g/mol

moles=38.7 g÷90.4 g/mol=0.4281   moles

step 2:   use the   mole ratio   to calculate the moles of o2

from equation above, liclo₃: o₂   is 2: 3  

therefore the moles of   o₂=0.4281 moles x3/2 =0.6422   moles

step 3: find mass   of o₂

mass= moles x molar mass

from periodic table the   molar mass of   o₂ = 16 x2= 32 g/mol

mass=0.6422   moles   x   32 g/mol = 20.6 grams of o₂

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