Find the moment of inertia ihoop of a hoop of radius r and mass m with respect to an axis perpendicular to the hoop and passing through its center.

MR²

is the the moment of inertia  of a hoop of radius R and mass M with respect to an axis perpendicular to the hoop and passing through its center

Explanation:

Since in the hoop , all mass elements  are situated at the same distance from the centre , the following expression for the moment of inertia can be written as follows.

I = ∫ r² dm

= R²∫ dm

MR²

where M is total mass and R is radius of the hoop .

a displacement distance is size of displ

that would be because of both gravity and friction. so     c