It takes 4.57 j of work to stretch a hooke’s-law spring 9.11 cm from its unstressed length. how much the extra work is required to stretch it an additional 9.54 cm? answer in units of j

Explanation:

Given that,

Work done, W = 4.57 J

Distance,

Distance,

We know that the work done by the spring is given by :

k = 550.65 N/m

To find,

Let is the extra work is required to stretch it an additional 9.54 cm. It can be calculated as :

W = 2207.96 J

So, the extra wok done is 2207.96 J.

iron would move it is magnetic there is a mag field around the current in the wire

t = 1/400 h   ⇔ 0.0025 h ⇔ 9s ⇔ 0.15 m

any of the answers are correct.