A500 kg car traveling at 20 m/s, brakes and skids to a stop. if μk = 0.7 between the tires and the road, the acceleration of the car during the skid is:

a. -0.7 m/s2

b. -7.0 m/s2

c. -2.0 m/s2

d. -0.2 m/s2

W= fd
where f is an applied force and d is the distance over which it is applied. when a parachuting skydiver is at constant velocity, he is experiencing "terminal velocity", the point at which his acceleration down is canceled out by air resistance. that means that the resisting force of the air is equal to his weight, but in the opposite direction. with this, we can solve for the work done by the force.
w = fd
w = (92.0)(9.81 m/s^2) (325)
w= 2.93 x 10^5 j
the value for work in this case is positive because it is pushing up on the skydiver, who has a downward force of gravity.
therefore the answer is 2.93 x 10^5 j

34 degrees fahrenheit

  the answer is don't know.