In a young’s double-slit experiment, the angle that locates the second dark fringe on either side of the central bright fringe is 5.4. find the ratio d/ of the slit separation d to the wavelength of the light. (d / λ) =?

d / λ = 26.7

Explanation:

In Young's double slit experiment, constructive interference is described by the expression

    d sin θ = m λ

In the case of destructive interference we must add half wavelength (λ/2)

    d siyn θ = (m + ½) λ

Let's clear

     d / λ = (m + ½) / sin θ

Let's calculate

    d / λ = (2+ ½) / sin 5.4

    d / λ = 5 / (2 sin 5.4)

    d / λ = 26.7

does anyone know or what?