Calculate the magnitude of q for a system that does 603000 kj of work on its surroundings and for which the change in total internal energy is −1.80 × 104 kj.

Q=585000 kJ

Explanation:

Given Data

W (Work)=603000 kJ

ΔU (Change in total internal energy)=-1.80×10⁴ kJ

Q (Heat Supplied)=?

Solution

First Law of thermodynamic:

The first law of thermodynamics states that energy can neither be created nor destroyed, but only converted between various forms. For a closed system, we may write the change in internal energy as:  

ΔU=Q-W

Q=ΔU+W

Q= -1.80×10⁴+603000

Q= 585000 kJ

diagram is missing, but i will try to explain your doubt.

answer:

amplitude is the maximum displacement or distance moved on a point of a vibrating body or wave measured from its equilibrium position.it is equal to half the length of vibration path.

c. newton's third law of motion