Two projectiles are fired from ground level at equal speeds but different angles. one is fired at an angle of 30° and the other at 60°. neglecting air resistance, the projectile to hit the ground first will be the one fired at

Explanation:

A projectile fired will be having two velocities horizontal velocity and vertical velocity.

If u is the velocity of firing

             Horizontal velocity = u cosθ

             Vertical velocity = u sinθ

Consider vertical motion of projectile, we have equation of motion

                v = u + at

      At maximum height

                 Final velocity, v = 0 m/s

                 Acceleration, a = -g = -9.81 m/s²

                Initial velocity, u = u sinθ

                0 = u sinθ - 9.81 x t

                Time of flight of projectile = 2 x t

Here for both projectiles initial velocity is same, time depends upon angle of projection.

                      sin 30 = 0.5

                      sin 60 = 0.866

So, maximum time is for the projectile which is projected at 60 degrees.

The one which one will be hitting ground first will be projectile launched at angle 30°.

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what is the speed of a softball that travels 20m in 2secs

speed = 20/2 = 10 m/s