Velocity down different ramps
20 degrees 30 degrees 40 degrees
0.5 seconds after release 1.5 m/s 1.7 m/s 1.8 m/s
1.0 seconds after release 2.9 m/s 3.3 m/s 3.5 m/s
1.5 seconds after release 4.3m/s 4.9 m/s 5.1 m/s

the table indicates the velocity of a marble as it is released down 3 ramps. the 3 ramps have different angles. the same marble was used for each test.
what does the table suggest about the acceleration of the marble and why?

Wooden , walls ,doors ,support

During the 1800s. hope this !

Distance covered, s = 8ft - 4ft = 4 ftinitial velocity, u = 34 ft/sthe acrobat is moving upwards and therefore, a = -g = -9.81 m/s^2 = 32.19 ft/s^2applying equation of motion; s = ut -1/2gt^2then,4 = 34t -1/2*32.19t^24 = 34t - 16.095t^2rearranging; -16.095t^2 + 34t - 4 = 0solving the quadratic equation; t = {-34 +/- sqrt [34^2 - 4(-16.)]}/2(-16.095) = 1.06 +/- 0.93 = 0.13 or 1.99the acrobat will take 0.13 seconds to be at 8 ft above the ground. additionally, once at the maximum height, the acrobat will move down and be at the same spot (that is height) after 1.99 seconds moving down.