A60kg block innitially at rest is pulled to the right a long a horizontal force of12n. find the speed of the block after it has moved 3m if the surface in contact have a coefficient of kinetic friction of 0.15

The speed of the block after it has moved 3M if the surface in contact have a coefficient of kinetic friction of 0.15  is 1.7s m/sec

Explanation:

Given:

mass of the block = 6.0 kg

Force with which the block is pulled = 12 N

Kinetic friction \mu= 0.15

Distance travelled  s = 3 m

To Find:

speed of the block after it has moved 3 metres =?

Solution :

W know that the friction formula is

Substituting the values,

Now Acceleration is Given by

a= 0.5

Initial velocity is u = 0

Also we know that,

So the equation becomes

Substituting the values,

v= 1.73 m/s

6 cos 34, 6 sin 34 trig