An automobile is started from rest with one of its doors initially at right angles. if the hinges of the door are toward the front of the car, the door will slam shut as the automobile picks up speed. obtain a formula for the time needed for the door to close if the acceleration f is constant, the radius of gyration of the door about the axis of rotation is r0, and the center of mass is at a distance a from the hinges. show that if f is 0.3 m/s^2 and the door is a uniform rectangle 1.2m wide, the time will be approximately 3.04 s. show all work.

newton's first law of motion

answer: (431,2)

step-by-step explanation:

true tan speed = ang vel x radius

the box does not move because you need to use a force greater than 300 n. you are only using 50 n. it needs to at least be 301 n for the box to move because then it is an unbalanced force and it will move the way that the greater force is pushing it. if you use only 300 n it will be a balanced force and will not move because the force you are exerting on the   box is the same as its force.

hope this !

im sorry if i went too in depth, i am going to include a link to a video on khan academy that will explain this.   hope that you like the video and that it explains more in detail to you.

that is the link.