Aparallel-plate capacitor is charged by connecting it to a battery. after that the capacitor is disconnected from the battery and a dielectric of dielectric constant κ is inserted. choose all correct statements about what happens to the quantities describing that capacitor:
the voltage across the capacitor decreases by a factor of 2.the voltage across the capacitor is doubled. the electric field is doubled. the charge on the plates decreases by a factor of 2.the charge on the plates is doubled.

The voltage across the capacitor decreases by a factor of 2.

Explanation:

As we know that capacitor is initially charges by battery connected across it

so we have

now capacitor is disconnected

so charge on the capacitor is conserved

Now a dielectric is inserted between the plates of the capacitor

So we will have

now the new voltage across the plates of capacitor is given as

so voltage between the plates of capacitor is decreased by factor of "k"

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explanation:

explanation:

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