Along pipe of outer radius =3.50 cm and inner radius =2.98 cm carries a uniform charge density of 9.22 mc/m3. assuming that the pipe is sufficiently long to consider it infinitely long, use gauss's law to calculate the electric field at a distance =7.35 cm from the centerline of the pipe. use =8.85×10−12 c/n·m2 for the the permittivity of free space.

2388078.86544 N/C

Explanation:

= Charge density = 9.22 mC/m³

r = Distance = 7.35 cm

= Outer radius = 3.5 cm

= Inner radius = 2.98 cm

l = Length of cylinder

= Permittivity of free space =

V = Volume

E = Electric field

Charge is given by

Area

From Gauss law the flux through a cylindrical surface is given by

The electric at the given distance is 2388078.86544 N/C

it is a negative acceleration

speed of light in vacuum is 300,000 km/s

speed of light in other mediums is given by the expression v = c/n, where c is the speed of light in vacuum and n is the refractive index of medium.

for the first medium v = 200,000 km/s

  so, refractive index of medium = 300000/200000 = 1.5

    1.5 refractive index is usually for glass. so first medium is glass.

for the second medium v = 250,00 km/s

so, refractive index of medium = 300000/250000 = 1.2

    1.2 refractive index is usually for water. so second medium is water.

for the third medium v = 0 km/s

so, refractive index of medium = 300000/0 = ∞

    ∞ refractive index is usually for opaque mediums. so third medium is opaque medium.