Amodel airplane with mass 0.741 kg is tethered to the ground by a wire so that it flies in a horizontal circle 30.5 m in radius. the airplane engine provides a net thrust of 0.804 n perpendicular to the tethering wire.
find the magnitude of the torque the net thrust produces about the center of the circle.

The magnitude of torque is τ = 24.522 N*m^2

Explanation:

To find the magnitude of the torque can use the equation of the force produce by the airplane so:

τ = F * d

τ = 0.804 N * 30.5 m

τ = 24.522 N*m

Check:

Find the acceleration

I = m*r^2=0.741kg*(30.5m)^2

I = 689.32 kg*m^2

τ = I*a_c

a_c = τ /I = 24.522 N*m^2 / 689.32 kg*m^2

a_c = 0.0355 m/s^2

τ = 0.0355 m/s^2 * 689.32 kg*m^2

τ = 24.522 N*m^2

energy stored in the capacitor= 9.72 x 10⁻⁴ j

explanation:

the energy stored in the capacitor is given by

e= 1/2 c v²

e= energy stored

c= capacitance= 1.5 µc= 1.5 x 10⁻⁶f

v= potential difference=36 v

so energy stored= e= 1/2 (1.5 x 10⁻⁶) (36)²

energy stored= 9.72 x 10⁻⁴j