Alight string is wrapped around the outer rim of a solid uniform cylinder of diameter 75.0 cm that can rotate without friction about an axle through its center. a 3.00 kg stone is tied to the free end of the string. when the system is released from rest, you determine that the stone reaches a speed of 3.40 m/s after having fallen 2.40 m. what is the mass of the cylinder?

Since a light string is wrapped around the outer rim of a solid uniform cylinder, the mass of the cylinder is equal to 18.4 kilograms.

Given the following data:

To calculate the mass of the cylinder:

First of all, we would determine the acceleration of the stone by using the the third equation of motion;

Where:

Substituting the given parameters into the formula, we have;

Acceleration, a = 2.41

Next, we would solve for the torque by using the formula:

Torque, T = 22.17 Newton.

In rotational motion, torque is given by the formula:

Mass = 18.4 kilograms

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18.5 kg

Explanation:

Given

diameter

mass of stone

velocity of stone

height fallen

using

Tension of string will Provide Torque to cylinder

where

and

Put value of T