Suppose that a commercial espresso machine in a coffee shop turns 1.50 kg of water at 22.0? c into steam at 100? c. if c=4187j/(kg? ? c) and hv=2,258kj/kg, how much heat q is absorbed by the water from the heating resistor inside the machine? assume that this is a closed and isolated system. express your answer in joules to three significant figures. q = j

Total heat required will be 555.756 KJ

Explanation:

We have given mass of the water m = 1.50 kg

Temperature is changes from to steam

Specific heat is given as c = 4718 J/kg

So amount of heat for changing the temperature from to

Heat of vaporization is given

So the amount of heat required to vaporize water

So total heat

we need answer choices

hello there!

your answer is a “generator”

a generator does not create energy but instead it transforms it.

it’s basically a motor working in reverse.