The new england merchants bank building in boston is 152 m high. on windy days it sways with a frequency of 0.14 hz , and the acceleration of the top of the building can reach 2.5 % of the free-fall acceleration, enough to cause discomfort for occupants.
what is the total distance, side to side, that the top of the building moves during such an oscillation?

Aliquid is an answer i hope this

Initial velocity,  u = 4.9 m/sfinal velocity = v m/sinitial height,  h₁ =  245 m    final height, h₂ = 0a = -9.8  m/s²time taken = t secondss = ut + 0.5at²⇒  (h₂-h₁) = ut + 0.5at²⇒  0-245 = 4.9t + 0.5×(-9.8)×t²⇒ -245 = 4.9t - 4.9t²⇒ 4.9t² -4.9t -245 =0solving it, we get   t = 7.59sv  = u +  at = 4.9 -9.8×7.59 = 4.9 - 74.38 = -69.48 m/svelocity is  69.48 m/s downward

Since the pully is a simple machine so the mechanical advantage is a 1