Agenerator produces 2 mw of electric power at 15 kv. the current is sent to a town 30 km away through aluminum transmission wires (resistivity 2.7 x 10-8 latex: \omega\cdot mω ⋅ m) with a diameter of 6.8 mm. what % of the electric power is lost during transmission?

To solve this problem it is necessary to apply the concepts related to Power in function of the current and the resistance.

By definition there are two ways to express power

P =VI

Where,

P = Power

I = Current

R = Resistance

V = Voltage

In our data we have the value for resistivity and not the Resistance, then

The loss of the potential can mainly be given by the resistance of the cables, that is,

Therefore the expression for power loss due to resistance is,

The total produced is , that is to say 100%, therefore 3.2872W is equivalent to,

Therefore the percentage of lost Power is equivalent to of the total

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explanation:

a charge 3q is at the origin, and a charge −2q is on the positive x axis at x=a. part a where on the x-axis would you place a third charge so it would experience no net electric force? enter an expression for the exact answer, which will involve a square-root sign. (do not enter an approximate decimal answer.)