An inductor with inductance l=25.4 mh and a resistor with resistance r=5.6 are wired in series to an ideal battery with voltage v=12 volts. a switch in the circuit is closed at time t=0 seconds, at which time the current is zero. what is the energy stored in the inductor?

Current in the circuit at the very instant after the switch is closed will be also 0

Energy stored  = 58.324 mJ

Explanation:

Inductor is a device which resists change in current in the circuit. Current in the circuit was 0 before the switch is closed. Therefore current in the circuit at the very instant after the switch is closed will be also 0. Since inductor resists change in current and likes to remain as it is.

After the switch is closed, current will be growing exponentially and finally will reach a steady state. Since we are considering the inductor as ideal, the resistance in the circuit will be only due to the resistor.

By ohm's law

V = IR

I =

V = 12 volts

R = 5.6 ohm

Substituting in the equation,

I =

I = 2.143 A

Again, we know that the energy stored in an inductor is given by

E =

L = 25.4 mH

I = 2.143 A

Substituting in the equation,

E =

E = 58.324 mJ

gpe = mass x gravity constant x height or… gpe = mgh

where… mass: measured in kilograms (kg)

gravity: gravity constant on earth = 10.00 m/s2

height: measured in meters (m)

gpe: measured in joules (j) or kilojoules (kj)

how do you solve gpe?

gravitational potential energy (gpe) is the energy an object has because of its position above the. ground.

gpe = mass x gravity constant x height or… gpe = mgh.

mass:

note: to earn full marks when solving science word problems, you must show your work:

formula.

example:

given values:

mass = 0.3 kg.