Ahorse is harnessed to a sled having a mass of 236 kg, includ- ing supplies. the horse must exert a force exceeding 1240 n at an angle of 35.0° in order to get the sled moving. treat the sled as a point particle.
(a) calculate the normal force on the sled when the magnitude of the applied force is 1240 n.
(b) find the coefficient of static friction between the sled and the ground beneath it.
(c) find the static friction force when the horse is exerting a force of 6.20 x 10^2 n on the sled at the same angle.

A = 1894.53N

B = 0.70

C = 0.327

Explanation:

Mass (m) = 236kg

F = 1240

Normal force (N) = ?

Θ = 35.0°

g = 9.8m/s²

Normal force (N) = mgcosΘ

N = 236 * 9.8 * cos 35

N = 1896.53N

B.

Coefficient of static friction μ =

F = μN

μ = F / N

μ = Mg sinΘ / mg cosΘ

μ = sinΘ / cosΘ

μ = tan Θ

μ = tan 35

μ = 0.700

Coefficient of static friction (μ) is 0.70

C. Static friction when the horse exerts a force of 6.20*10²N

F = μN

μ = F / N

F = 6.20*10²

N = 1894.53N

μ = 620 / 1894.53

μ = 0.327

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