The international space station orbits at an average height of 350 km above sea = 6.67× 10−11 ⁄ ℎ = 5.97 × 1024 ℎ = 6.37× 103 (a) determine the orbital speed of this space station.(b) the period of the space station. draw it out for full credit

(a). The orbital speed of this space station is 7906.42 m/s.

(b).  The period of the space station is 5062.2 sec.

Explanation:

Given that,

Gravitational constant

Mass of earth

Radius of earth

(a). We need to calculate the orbital speed of this space station

Using formula of orbital speed

(b). We need to calculate the period of the space station

Using formula of period

Put the value into the formula

Hence, (a). The orbital speed of this space station is 7906.42 m/s.

(b).  The period of the space station is 5062.2 sec.

we need to know the time interval during which the force acts. impulse of force = momentum change