Coherent light that contains two wavelengths, 660 nm (red) and 470 nm (blue), passes through two narrow slits that are separated by 0.300 mm. their interference pattern is observed on a screen 4.00 m from the slits. what is the distance on the screen between the first-order bright fringes for the two wavelengths?

0.00254 m or 2.54 mm

Explanation:

y = Fringe distance

d= Distance between slits = 0.3 mm

L = Screen distance = 4 m

= Wavelength

In the case of constructive interference

For first order wavelength

The distance between the fringes is given by

The distance on the screen between the first-order bright fringes for the two wavelengths is 0.00254 m or 2.54 mm

acceleration = (change in speed) / (time for the change)

change in speed = (20-120)= -100 m/s.

1.5 min = 90 sec

acceleration = -100/90 = -1.11 m/s^2.

we don't care about the 150kg or the 2,500 meters. they don't make any difference.

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