You a building a circuit that requires a 150 pf capacitor, but you only have a drawer full of 100 pf capacitors.

(how) can you make a 150 pf equivalent capacitor?

To develop this problem it is necessary to apply the concepts of sum of capacitors in a circuit, either in parallel or in series.

When capacitors are connected in series, they consecutively add their capacitance.

However, when they are connected in parallel, the sum that is made is that of the inverse of the capacitance, that is where, C is the capacitance.

For the given case, it is best to connect two of these capacitors in series and one in parallel, so

We have three 100 pF capacitors, then

Here we can see how two capacitors 1 and 2 are in series and the third in parallel.

Investing equality

Adding it in parallel, then

kinetic

i'm so sorry if this is wrong i'm only in 6th grade xd

true is the correct answer

hope i