Abasketball of mass 0.55 kg is dropped from rest from a height of 1.22 m. it rebounds to a height of 0.40 m.
(a) how much mechanical energy was lost during the collision with the floor? j
(b) a basketball player dribbles the ball from a height of 1.22 m by exerting a constant downward force on it for a distance of 0.13 m. in dribbling, the player compensates for the mechanical energy lost during each bounce. if the ball now returns to a height of 1.22 m, what is the magnitude of the force?

fgravity=10x10=100n case 1

fgravity=30x20=600n case 2

6 times more

like poles repel so keep pushing north to north and repels funny to see this

initial speed when it is dropped is 150 ft/s

now at the same moment the acceleration due to gravity is perpendicular to its velocity

so as we know that

now we have centripetal acceleration a = 32 ft/s^2 as its perpendicular to velocity

while tangential acceleration at the same moment will be zero

so

now radius of curvature is given as

so the radius of curvature just after it is dropped is 703.125 ft